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Antibody history and antigen-negative units

16 min

  • Select red cells using current and historical significant antibodies
  • Estimate how many units to screen from antigen-negative donor frequencies

Read the full reference

Try first

Try first

A patient's record shows anti-Jka identified 3 years ago. Today's antibody screen is nonreactive, and a Jk(a+) red cell unit is compatible through the antiglobulin phase. What can happen if that unit is transfused?

The next section explains it.

The next section explains it.

Right. The next section explains why.

The next section explains it.

Get the idea

The record outlasts the antibody

Many alloantibodies fall below detection within months to years, and Kidd antibodies do so often.1,2 The memory B cells that made the antibody remain. Antigen-positive red cells can set off an anamnestic response. The antibody returns within days and shortens the survival of the transfused cells, which is a delayed hemolytic transfusion reaction.1,3

An antibody is clinically significant when it can shorten the survival of antigen-positive red cells or cause hemolytic disease of the fetus and newborn. Most Rh, Kell, Kidd, Duffy, S and s antibodies qualify.1 Laboratory policy may allow crossmatch-compatible units for an antibody judged insignificant by validated testing, such as an anti-M that reacts only at room temperature.1,4

The transfusion service therefore checks the antibody record before every red cell selection:1,4,5

  1. List every clinically significant antibody ever identified, from today's panel and from the record.
  2. Select red cells that lack every one of those antigens.
  3. Crossmatch through the antiglobulin phase. A current or past clinically significant antibody excludes the patient from the electronic crossmatch.
  4. Keep the antibody on the record for every future specimen.

Estimating the search

Estimated compatible fraction = product of the independent antigen-negative fractions among ABO-compatible units. Units to screen = units needed ÷ compatible fraction, rounded up. Linked antigens and local donor frequencies change the estimate. The fractions multiply because these antigens are inherited independently.1 Approximate figures for donors of European ancestry:1,6

AntigenDonors lacking it
K91%
E70%
c20%
Fya34%
Jka23%
S45%

Frequencies differ between populations. Most donors of African ancestry lack Fya, for example.1,6 The blood bank's own donor data refine the estimate. Candidate units are typed with antisera, and only the negative ones go on to the crossmatch. When the compatible fraction is very small, the blood supplier can send units already typed for those antigens.1 An estimate is an average and cannot promise the units, so plan to test more if the first set falls short.1

References
  1. Bloch EM, Campbell-Lee S, McKenna DH Jr, Montemayor-Garcia C, Schwartz J, Shaz B, Storry J, eds. Technical Manual. 22nd ed. AABB; 2026.
  2. Hendrickson JE, Eisenbarth SC, Tormey CA. Red blood cell alloimmunization: new findings at the bench and new recommendations for the bedside. Curr Opin Hematol. 2016;23(6):543-549. doi:10.1097/MOH.0000000000000277
  3. Arthur CM, Chonat S, Fasano R, et al. Examining the role of complement in predicting, preventing, and treating hemolytic transfusion reactions. Transfus Med Rev. 2019;33(4):217-224. doi:10.1016/j.tmrv.2019.09.006
  4. Association for the Advancement of Blood & Biotherapies. Fundamental Standards for Blood Collection and Transfusion. 2nd ed. AABB; 2025. Accessed September 27, 2026. https://www.aabb.org/docs/default-source/default-document-library/standards/fundamental-standards-for-blood-collection-and-transfusion-2nd-ed.pdf?sfvrsn=caa34314_3
  5. US Food and Drug Administration. Computer Crossmatch: Computerized Analysis of the Compatibility Between the Donor's Cell Type and the Recipient's Serum or Plasma Type. Guidance for Industry. April 2011. Accessed September 27, 2026. https://www.fda.gov/media/80857/download
  6. Harmening DM, ed. Modern Blood Banking & Transfusion Practices. 7th ed. F.A. Davis; 2019.

Watch one

A woman's record lists anti-Jka identified in 2023. She needs 2 units of red cells. Today's panel:

Using the briefing's frequencies, how many ABO-compatible units should be antigen-typed to find 2 suitable units?

Antibody panel: + the cell carries the antigen, 0 it lacks it
CellDCEceKkFyaFybJkaJkbMNSsIS37AHG
1++00+0++0+0+0+0000
2++00+++0+0+++0+000
3+0++00+++++0+++0w+3+
40+0++0+0+0+++0+000
500+++0++0+++0++002+
6000+++++++00+++000
7000++0+0+++++0+000
8+00++0+++0+0+++000
9+0+++++0++0++0+002+
10000++0++00++00+000
11000++0+0++00++0000
Autocontrol000
  1. List the antibodies. Today's panel shows anti-E in cells 3, 5 and 9. The record adds anti-Jka.

    The historical antibody counts even though the Jk(a+b−) cells 1, 6 and 11 are nonreactive today.

  2. Take the negative fractions: E-negative 0.70, Jk(a−) 0.23.

    The estimate uses the donors who lack each antigen.

  3. Multiply: 0.70 × 0.23 = 0.161.

    Independent antigens combine by multiplication, so about 16% of donors lack both.

  4. Divide: 2 ÷ 0.161 = 12.4.

    Units needed divided by the compatible fraction gives the average number to test.

  5. Round up to 13 units.

    Part of a unit cannot be tested, and rounding down plans too few.

  6. Type the units for E and Jka, and crossmatch the negative ones through the antiglobulin phase.

    The estimate sizes the search. Each unit still needs typing and a crossmatch.

About 13 units: 2 ÷ (0.70 × 0.23) = 2 ÷ 0.161 = 12.4, rounded up to 13.

Your turn

Problem 1 of 3

A patient's record shows a Kidd antibody identified 2 years ago. Today's antibody screen is nonreactive. Which red cells are selected for transfusion?

Incorrect. A history of a clinically significant antibody excludes the electronic crossmatch. The patient needs antigen-negative units and a crossmatch through the antiglobulin phase, whatever today's screen shows.

Correct. Kidd antibodies such as anti-Jka can fall below routine detection and return quickly after re-exposure, shortening donor-cell survival. The recorded antibody still decides unit selection.

Incorrect. A Kidd antibody below detection can give a compatible crossmatch with antigen-positive cells, which then recruit memory B cells and set off an anamnestic response.

Hint
  1. Ask what happens to the cells that made the antibody after the antibody level falls.
  2. Think about what antigen-positive red cells would do to those cells.

Review Anti-Jka with a nonreactive screen

Antibody panel: + the cell carries the antigen, 0 it lacks it
CellDCEceKkFyaFybJkaJkbMNSsIS37AHG
1++00+0++0+++00+002+
2++00+++0++0+++0000
3+0++00+0+0+0+0+000
40+0++0+++0+++++001+
500+++0+0++++0++000
6000++++0++00+0+000
7000++0++00+++++002+
8+00++0+0+0++0+0000
9000++0+0+++++0+000
10+++++0++++0++0+001+
11000++0+++++0+++001+
Autocontrol000
Problem 2 of 3

A man's panel today identifies anti-Fya. His record shows anti-K identified 4 years ago, and the K+ cells 2 and 6 are nonreactive today. Which red cells does he receive?

Anti-K can fall below detection and return after exposure to K. The record still decides, so his units are K-negative too.

Ignored a historical antibody after a negative screen

Kidd and other antibodies can fall below detection, and the memory B cells that made them remain. Antigen-positive red cells can then trigger an anamnestic response and a delayed hemolytic reaction days after transfusion, so a documented clinically significant antibody still requires antigen-negative units and an antiglobulin crossmatch.

Today's anti-Fya is clinically significant too. Every antibody, current and historical, sets a requirement.

A current or past clinically significant antibody excludes him from the electronic crossmatch. His units need a serologic crossmatch through the antiglobulin phase.

Today's panel sets Fy(a−), and the record sets K-negative. The antiglobulin crossmatch checks for IgG incompatibility with each unit.

Hint
  1. List every antibody he has ever had, from the panel and from the record.
  2. Ask whether a nonreactive K+ cell today shows that his anti-K is gone for good.

Review Unit selection and availability

Problem 3 of 3

A patient has anti-K and anti-S and needs 3 units of red cells. The blood bank's donor data show 91% of units lack K and 45% lack S. How many ABO-compatible units should be antigen-typed?

Show the answer

8 units

Compatible fraction = 0.91 × 0.45 = 0.4095. Units to type = 3 ÷ 0.4095 = 7.3, rounded up to 8. Multiplying the antigen-positive fractions by mistake gives 0.09 × 0.55 = 0.0495 and 61 units.

Review Unit selection and availability

Use it

  • Grace Whitlock, 64, a church choir director (MRN 3308145), is scheduled for a knee replacement tomorrow. The surgeon asks for 2 units of red cells.
  • Today's panel identifies anti-K. Her autocontrol is nonreactive.
  • A record from another hospital, sent with her referral, lists anti-Jka identified in 2021.
  • Her plasma is nonreactive with every Jk(a+) panel cell today.
  • The blood bank's donor data: 91% of units lack K, and 23% lack Jka.
Decision 1 of 3

Which red cells does she need?

Anti-Jka is known for falling below detection and returning after exposure. The outside record counts as fully as today's panel.

Ignored a historical antibody after a negative screen

Kidd and other antibodies can fall below detection, and the memory B cells that made them remain. Antigen-positive red cells can then trigger an anamnestic response and a delayed hemolytic reaction days after transfusion, so a documented clinically significant antibody still requires antigen-negative units and an antiglobulin crossmatch.

Today's panel sets K-negative, and the record sets Jk(a−). The antiglobulin crossmatch completes the selection.

An immediate-spin crossmatch detects ABO incompatibility. A patient with clinically significant antibodies needs a crossmatch through the antiglobulin phase.

Review Unit selection and availability

Decision 2 of 3

About how many ABO-compatible units should be antigen-typed to find 2?

2 ÷ 0.91 = 2.2 counts only the K requirement. Each unit must also be Jk(a−): 2 ÷ (0.91 × 0.23) = 9.6, rounded up to 10.

Ignored a historical antibody after a negative screen

Kidd and other antibodies can fall below detection, and the memory B cells that made them remain. Antigen-positive red cells can then trigger an anamnestic response and a delayed hemolytic reaction days after transfusion, so a documented clinically significant antibody still requires antigen-negative units and an antiglobulin crossmatch.

2 ÷ (0.91 × 0.23) = 9.6. Rounding down plans for fewer units than the average needs, so the estimate rounds up to 10.

That uses the fractions that carry the antigens: 0.09 × 0.77 = 0.069. The search depends on the fractions that lack them, 0.91 × 0.23 = 0.209, which gives 10 units.

Used antigen-positive frequencies for the unit estimate

The compatible fraction multiplies the fractions of donors who lack each antigen. With the lesson's figures, the antigen-negative product 0.91 × 0.27 = 0.246 gives 13 units to screen for 3. Multiplying the antigen-positive fractions by mistake, 0.09 × 0.73 = 0.066, gives 46. Linked antigens and local donor data also change the simple product.

0.91 × 0.23 = 0.209, and 2 ÷ 0.209 = 9.6, rounded up to 10.

Review Unit selection and availability

Decision 3 of 3

The 10 units are typed, and only 1 is K-negative and Jk(a−). What happens next?

The estimate is an average, and a first set can fall short. The search continues, and the surgical team is told when the second unit will be ready.

Her anti-Jka is below detection, so a Jk(a+) unit can crossmatch compatible. It can still set off an anamnestic response and a delayed hemolytic reaction.

Ignored a historical antibody after a negative screen

Kidd and other antibodies can fall below detection, and the memory B cells that made them remain. Antigen-positive red cells can then trigger an anamnestic response and a delayed hemolytic reaction days after transfusion, so a documented clinically significant antibody still requires antigen-negative units and an antiglobulin crossmatch.

The calculation was right. It gives the average number to test, and one set of 10 can yield fewer.

Review Unit selection and availability

The clue that settled this case is the outside record of anti-Jka. Today's panel could not show that antibody, and it still set a second requirement. It shrank the compatible fraction from 91% to about 21%, which is why the search grew from 3 units to 10.

Keep

Sources checked