Antibody history and antigen-negative units
16 min
- Select red cells using current and historical significant antibodies
- Estimate how many units to screen from antigen-negative donor frequencies
Try first
Get the idea
The record outlasts the antibody
Many alloantibodies fall below detection within months to years, and Kidd antibodies do so often.1,2 The memory B cells that made the antibody remain. Antigen-positive red cells can set off an anamnestic response. The antibody returns within days and shortens the survival of the transfused cells, which is a delayed hemolytic transfusion reaction.1,3
An antibody is clinically significant when it can shorten the survival of antigen-positive red cells or cause hemolytic disease of the fetus and newborn. Most Rh, Kell, Kidd, Duffy, S and s antibodies qualify.1 Laboratory policy may allow crossmatch-compatible units for an antibody judged insignificant by validated testing, such as an anti-M that reacts only at room temperature.1,4
The transfusion service therefore checks the antibody record before every red cell selection:1,4,5
- List every clinically significant antibody ever identified, from today's panel and from the record.
- Select red cells that lack every one of those antigens.
- Crossmatch through the antiglobulin phase. A current or past clinically significant antibody excludes the patient from the electronic crossmatch.
- Keep the antibody on the record for every future specimen.
Estimating the search
Estimated compatible fraction = product of the independent antigen-negative fractions among ABO-compatible units. Units to screen = units needed ÷ compatible fraction, rounded up. Linked antigens and local donor frequencies change the estimate. The fractions multiply because these antigens are inherited independently.1 Approximate figures for donors of European ancestry:1,6
| Antigen | Donors lacking it |
|---|---|
| K | 91% |
| E | 70% |
| c | 20% |
| Fya | 34% |
| Jka | 23% |
| S | 45% |
Frequencies differ between populations. Most donors of African ancestry lack Fya, for example.1,6 The blood bank's own donor data refine the estimate. Candidate units are typed with antisera, and only the negative ones go on to the crossmatch. When the compatible fraction is very small, the blood supplier can send units already typed for those antigens.1 An estimate is an average and cannot promise the units, so plan to test more if the first set falls short.1
References
- Bloch EM, Campbell-Lee S, McKenna DH Jr, Montemayor-Garcia C, Schwartz J, Shaz B, Storry J, eds. Technical Manual. 22nd ed. AABB; 2026.
- Hendrickson JE, Eisenbarth SC, Tormey CA. Red blood cell alloimmunization: new findings at the bench and new recommendations for the bedside. Curr Opin Hematol. 2016;23(6):543-549. doi:10.1097/MOH.0000000000000277
- Arthur CM, Chonat S, Fasano R, et al. Examining the role of complement in predicting, preventing, and treating hemolytic transfusion reactions. Transfus Med Rev. 2019;33(4):217-224. doi:10.1016/j.tmrv.2019.09.006
- Association for the Advancement of Blood & Biotherapies. Fundamental Standards for Blood Collection and Transfusion. 2nd ed. AABB; 2025. Accessed September 27, 2026. https://www.aabb.org/docs/default-source/default-document-library/standards/fundamental-standards-for-blood-collection-and-transfusion-2nd-ed.pdf?sfvrsn=caa34314_3
- US Food and Drug Administration. Computer Crossmatch: Computerized Analysis of the Compatibility Between the Donor's Cell Type and the Recipient's Serum or Plasma Type. Guidance for Industry. April 2011. Accessed September 27, 2026. https://www.fda.gov/media/80857/download
- Harmening DM, ed. Modern Blood Banking & Transfusion Practices. 7th ed. F.A. Davis; 2019.
Watch one
A woman's record lists anti-Jka identified in 2023. She needs 2 units of red cells. Today's panel:
Using the briefing's frequencies, how many ABO-compatible units should be antigen-typed to find 2 suitable units?
| Cell | D | C | E | c | e | K | k | Fya | Fyb | Jka | Jkb | M | N | S | s | IS | 37 | AHG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1 | + | + | 0 | 0 | + | 0 | + | + | 0 | + | 0 | + | 0 | + | 0 | 0 | 0 | 0 |
| 2 | + | + | 0 | 0 | + | + | + | 0 | + | 0 | + | + | + | 0 | + | 0 | 0 | 0 |
| 3 | + | 0 | + | + | 0 | 0 | + | + | + | + | + | 0 | + | + | + | 0 | w+ | 3+ |
| 4 | 0 | + | 0 | + | + | 0 | + | 0 | + | 0 | + | + | + | 0 | + | 0 | 0 | 0 |
| 5 | 0 | 0 | + | + | + | 0 | + | + | 0 | + | + | + | 0 | + | + | 0 | 0 | 2+ |
| 6 | 0 | 0 | 0 | + | + | + | + | + | + | + | 0 | 0 | + | + | + | 0 | 0 | 0 |
| 7 | 0 | 0 | 0 | + | + | 0 | + | 0 | + | + | + | + | + | 0 | + | 0 | 0 | 0 |
| 8 | + | 0 | 0 | + | + | 0 | + | + | + | 0 | + | 0 | + | + | + | 0 | 0 | 0 |
| 9 | + | 0 | + | + | + | + | + | 0 | + | + | 0 | + | + | 0 | + | 0 | 0 | 2+ |
| 10 | 0 | 0 | 0 | + | + | 0 | + | + | 0 | 0 | + | + | 0 | 0 | + | 0 | 0 | 0 |
| 11 | 0 | 0 | 0 | + | + | 0 | + | 0 | + | + | 0 | 0 | + | + | 0 | 0 | 0 | 0 |
| Autocontrol | 0 | 0 | 0 |
- List the antibodies. Today's panel shows anti-E in cells 3, 5 and 9. The record adds anti-Jka.
The historical antibody counts even though the Jk(a+b−) cells 1, 6 and 11 are nonreactive today.
- Take the negative fractions: E-negative 0.70, Jk(a−) 0.23.
The estimate uses the donors who lack each antigen.
- Multiply: 0.70 × 0.23 = 0.161.
Independent antigens combine by multiplication, so about 16% of donors lack both.
- Divide: 2 ÷ 0.161 = 12.4.
Units needed divided by the compatible fraction gives the average number to test.
- Round up to 13 units.
Part of a unit cannot be tested, and rounding down plans too few.
- Type the units for E and Jka, and crossmatch the negative ones through the antiglobulin phase.
The estimate sizes the search. Each unit still needs typing and a crossmatch.
Your turn
| Cell | D | C | E | c | e | K | k | Fya | Fyb | Jka | Jkb | M | N | S | s | IS | 37 | AHG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1 | + | + | 0 | 0 | + | 0 | + | + | 0 | + | + | + | 0 | 0 | + | 0 | 0 | 2+ |
| 2 | + | + | 0 | 0 | + | + | + | 0 | + | + | 0 | + | + | + | 0 | 0 | 0 | 0 |
| 3 | + | 0 | + | + | 0 | 0 | + | 0 | + | 0 | + | 0 | + | 0 | + | 0 | 0 | 0 |
| 4 | 0 | + | 0 | + | + | 0 | + | + | + | 0 | + | + | + | + | + | 0 | 0 | 1+ |
| 5 | 0 | 0 | + | + | + | 0 | + | 0 | + | + | + | + | 0 | + | + | 0 | 0 | 0 |
| 6 | 0 | 0 | 0 | + | + | + | + | 0 | + | + | 0 | 0 | + | 0 | + | 0 | 0 | 0 |
| 7 | 0 | 0 | 0 | + | + | 0 | + | + | 0 | 0 | + | + | + | + | + | 0 | 0 | 2+ |
| 8 | + | 0 | 0 | + | + | 0 | + | 0 | + | 0 | + | + | 0 | + | 0 | 0 | 0 | 0 |
| 9 | 0 | 0 | 0 | + | + | 0 | + | 0 | + | + | + | + | + | 0 | + | 0 | 0 | 0 |
| 10 | + | + | + | + | + | 0 | + | + | + | + | 0 | + | + | 0 | + | 0 | 0 | 1+ |
| 11 | 0 | 0 | 0 | + | + | 0 | + | + | + | + | + | 0 | + | + | + | 0 | 0 | 1+ |
| Autocontrol | 0 | 0 | 0 |
Use it
- Grace Whitlock, 64, a church choir director (MRN 3308145), is scheduled for a knee replacement tomorrow. The surgeon asks for 2 units of red cells.
- Today's panel identifies anti-K. Her autocontrol is nonreactive.
- A record from another hospital, sent with her referral, lists anti-Jka identified in 2021.
- Her plasma is nonreactive with every Jk(a+) panel cell today.
- The blood bank's donor data: 91% of units lack K, and 23% lack Jka.
The clue that settled this case is the outside record of anti-Jka. Today's panel could not show that antibody, and it still set a second requirement. It shrank the compatible fraction from 91% to about 21%, which is why the search grew from 3 units to 10.
Results
- Select red cells using current and historical significant antibodies
- Estimate how many units to screen from antigen-negative donor frequencies
To review
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